Abstract
In this article, we establish some common fixed point theorems for a hybrid pair {g, T} of single valued and multi-valued maps satisfying a generalized contractive condition defined on G-metric spaces. Our results unify, generalize and complement various known comparable results from the current literature.
2000 MSC: 54H25; 47H10; 54E50.
Keywords:
multi-valued mappings; common fixed point; weakly compatible mappings; generalized contraction1. Introduction and preliminaries
Nadler [1] initiated the study of fixed points for multi-valued contraction mappings and generalized the well known Banach fixed point theorem. Then after, many authors studied many fixed point results for multi-valued contraction mappings see [2-13].
Mustafa and Sims [14] introduced the G-metric spaces as a generalization of the notion of metric spaces. Mustafa et al. [15-19] obtained some fixed point theorems for mappings satisfying different contractive conditions. Abbas and Rhoades [20] initiated the study of common fixed point in G-metric spaces. While Saadati et al. [21] studied some fixed point theorems in generalized partially ordered G-metric spaces. Gajić and Crvenković [22,23] proved some fixed point results for mappings with contractive iterate at a point in G-metric spaces. For other studies in G-metric spaces, we refer the reader to [24-38]. Consistent with Mustafa and Sims [14], the following definitions and results will be needed in the sequel.
Definition 1.1. (See [14]). Let X be a non-empty set, G : X × X × X → ℝ+ be a function satisfying the following properties
(G1) G(x, y, z) = 0 if x = y = z,
(G2) 0 < G(x, x, y) for all x, y ∈ X with x ≠ y,
(G3) G(x, x, y) ≤ G(x, y, z) for all x, y, z ∈ X with y ≠ z,
(G4) G(x, y, z) = G(x, z, y) = G(y, z, x) = ... (symmetry in all three variables),
(G5) G(x, y, z) ≤ G(x, a, a) + G(a, y, z) for all x, y, z, a∈X (rectangle inequality).
Then the function G is called a generalized metric, or, more specially, a G-metric on X, and the pair (X, G) is called a G-metric space.
Definition 1.2. (See [14]). Let (X, G) be a G-metric space, and let (xn) be a sequence of points of X, therefore, we say that (xn) is G-convergent to x ∈ X if
, that is, for any ε > 0, there exists N ∈ ℕ such that G(x, xn, xm) < ε, for all n, m ≥ N. We call x the limit of the sequence and write xn → x or 
Proposition 1.1. (See [14]). Let (X, G) be a G-metric space. The following statements are equivalent:
(1) (xn) is G-convergent to x,
(2) G(xn, xn, x) → 0 as n → +∞,
(3) G(xn, x, x) → 0 as n → +∞,
(4) G(xn, xm, x) → 0 as n, m → +∞.
Definition 1.3. (See [14]). Let (X, G) be a G-metric space. A sequence (xn) is called a G-Cauchy sequence if for any ε > 0, there is N ∈ ℕ such that G(xn, xm, xl) < ε for all m, n, l ≥ N, that is, G(xn, xm, xl) → 0 as n, m, l → +∞.
Proposition 1.2. (See [14]). Let (X, G) be a G-metric space. Then the following statements are equivalent:
(1) the sequence (xn) is G-Cauchy,
(2) for any ε > 0, there exists N ∈ ℕ such that G(xn, xm, xm) < ε, for all m, n ≥ N.
Definition 1.4. (See [14]). A G-metric space (X, G) is called G-complete if every G-Cauchy sequence is G-convergent in (X,G).
Every G-metric on X defines a metric dG on X given by
Recently, Kaewcharoen and Kaewkhao [34] introduced the following concepts. Let X be a G-metric space. We shall denote CB(X) the family of all nonempty closed bounded subsets of X. Let H(.,.,.) be the Hausdorff G-distance on CB(X), i.e.,
where
Recall that G(x, y, C) = inf {G(x, y, z), z ∈ C}. A mapping T : X → 2X is called a multi-valued mapping. A point x ∈ X is called a fixed point of T if x ∈ Tx.
Definition 1.5. Let X be a given non empty set. Assume that g : X → X and T : X → 2X.
If w = gx ∈ Tx for some x ∈ X, then x is called a coincidence point of g and T and w is a point of coincidence of g and T.
Mappings g and T are called weakly compatible if gx ∈ Tx for some x ∈ X implies gT(x) ⊆ Tg(x).
Proposition 1.3. (see [34]). Let X be a given non empty set. Assume that g : X → X and T : X → 2X are weakly compatible mappings. If g and T have a unique point of coincidence w = gx∈ Tx, then w is the unique common fixed point of g and T.
In this article, we establish some common fixed point theorems for a hybrid pair {g,T} of single valued and multi-valued maps satisfying a generalized contractive condition defined on G-metric spaces. Also, an example is presented.
2. Main results
We start this section with the following lemma, which is the variant of the one given in Nadler [1] or Assad and Kirk [4]. Its proof is a simple consequence of the definition of the Hausdorff G-distance HG(A, B, B).
Lemma 2.1. If A, B ∈ CB(X) and a ∈ A, then for each ε > 0, there exists b ∈ B such that G(a,b,b) ≤ HG(A, B, B) + ε.
The main result of the article is the following.
Theorem 2.1. Let (X, G) be a G-metric space. Set g : X → X and T : X → CB(X). Assume that there exists a function α : [0,+∞) → [0,1) satisfying
for every t ≥ 0 such that
for all x, y, z ∈ X. If for any x ∈ X, Tx ⊆ g(X) and g(X) is a G-complete subspace of X, then g and T have a point of coincidence in X. Furthermore, if we assume that gp ∈ Tp and gq ∈ Tq implies G(gq, gp, gp) ≤ HG(Tq, Tp, Tp), then
(i) g and T have a unique point of coincidence.
(ii) If in addition g and T are weakly compatible, then g and T have a unique common fixed point.
Proof. Let x0 be arbitrary in X. Since Tx0 ⊆ g(X), choose x1 ∈ X such that gx1 ∈ Tx0. If gx1= gx0, we finished. Assume that gx0 ≠ gx1, so G(gx0, gx1, gx1) > 0. We can choose a positive integer n1 such that
By Lemma 2.1 and the fact that Tx1 ⊆ g(X), there exists gx2 ∈ Tx1 such that
Using the two above inequalities and (2), it follows that
If gx1 = gx2, we finished. Assume that gx1 ≠ gx2. Now we choose a positive integer n2> n1 such that
Since Tx2 ∈ CB(X) and the fact that Tx2 ⊆ g(X), we may select gx3 ∈ Tx2 such that from Lemma 2.1
and then, similarly to the previous case, we have
By repeating this process, for each k ∈ ℕ*, we may choose a positive integer nk such that
Again, we may select gxk+1 ∈ Txk such that
The last two inequalities together imply that
which shows that the sequence of nonnegative numbers {dk}, given by dk = G(gxk-1, gxk, gxk), k = 1, 2,. . ., is non-increasing. This means that there exists d ≥ 0 such that
Let now prove that the {gxk} is a G-Cauchy sequence.
Using the fact that, by hypothesis for t = d,
, it results that there exists a rank k0 such that for k ≥ k0, we have α(dk) < h, where
Now, by (3) we deduce that the sequence {dk} satisfies the following recurrence inequality
By induction, from (4), we get
which, by using the fact that α < 1, can be simplified to
Referring to the proof of Theorem 2.1 in [11] or Lemma 3.2 in [12], we may obtain
where c is a positive constant. We deduce that
Now for k ≥ k0 and m is a positive arbitrary integer, we have using the property (G4)
since 0 < h < 1. This shows that the sequence {gxn} is G-Cauchy in the complete subspace g(X). Thus, there exists q ∈ g(X) such that, from Proposition 1.1
Since q ∈ g(X), then there exists p ∈ X such that q = gp. From (5), we have
We claim that gp ∈ Tp. Indeed, from (2), we have
Letting n → +∞ in (7) and using (6), we get
that is, gp ∈ Tp. That is T and g have a point of coincidence. Now, assume that if gp ∈ Tp and gq ∈ Tq, then G(gq, gp, gp) ≤ HG(Tq, Tp, Tp). We will prove the uniqueness of a point of coincidence of g and T. Suppose that gp ∈ Tp and gq ∈ Tq. By (2) and this assumption, we have
and since α(G(gq, gp, gp)) < G(gq, gp, gp), so necessarily from (8), we have G(gq, gp, gp) = 0, i.e., gp = gq. In view of
we get Tq = Tp. Thus, T and g have a unique point of coincidence. Suppose that g and T are weakly compatible. By applying Proposition 1.3, we obtain that g and T have a unique common fixed point.
Corollary 2.1. Let (X,G) be a complete G-metric space. Assume that T : X → CB(X) satisfies the following condition
for all x, y, z ∈ X, where α : [0,+∞) → [0,1) satisfies
for every t ≥ 0. Then T has a fixed point in X. Furthermore, if we assume that p ∈ Tp and q ∈ Tq implies G(q, p, p) ≤ HG(Tq, Tp, Tp), then T has a unique fixed point.
Proof. It follows by taking g the identity on X in Theorem 2.1.
Corollary 2.2. Let (X, G) be a G-metric space. Assume that g : X → X and T : X → CB(X) satisfy the following condition
for all x, y, z ∈ X, where k ∈ [0,1). If for any x ∈ X, Tx ⊆ g(X) and g(X) is a G-complete subspace of X, then g and T have a point of coincidence in X. Furthermore, if we assume that gp ∈ Tp and gq ∈ Tq implies G(gq, gp, gp) ≤ HG(Tq, Tp, Tp), then
(i) g and T have a unique point of coincidence.
(ii) If in addition g and T are weakly compatible, then g and T have a unique common fixed point.
Proof. It follows by taking α(t) = k, k ∈ [0,1), in Theorem 2.1.
In the case of single-valued mappings, that is, if T : X → X, (i.e., Tx = {Tx} for any x ∈ X), it is obviously that
Furthermore, if gp ∈ Tp (i.e., gp = Tp) and gq ∈ Tq (i.e., gq = Tq), then clearly,
that is, the assumption given in Theorem 2.1 is verified.
Also, the single-valued mappings T, g : X → X are said weakly compatible if Tgx = gTx whenever Tx = gx for some x ∈ X.
Now, we may state the following corollaries from Theorem 2.1 and the precedent corollaries:
Corollary 2.3. Let (X, G) be a complete G-metric space. Assume that T : X → X satisfies the following condition
for all x, y, z ∈ X, where α : [0, +∞) → [0, 1) satisfies
for every t ≥ 0. Then, T has a unique fixed point.
Corollary 2.4. Let (X, G) be a G-metric space. Assume that g : X → X and T : X → X satisfy the following condition
for all x, y, z ∈ X, where α : [0, +∞) → [0, 1) satisfies
for every t ≥ 0. If T(X) ⊆ g(X) and g(X) is a G-complete subspace of X, then
(i) g and T have a unique point of coincidence.
(ii) Furthermore, if g and T are weakly compatible, then g and T have a unique common fixed point.
Now, we introduce an example to support the useability of our results.
Example 2.1. Let X = [0, 1]. Define T : X → CB(X) by
and define g : X → X by
. Define a G-metric on X by G(x, y, z) = max{|x-y|, |x-z|, |y-z|}. Also, define α : [0, +∞) → [0, 1) by
Then:
(1) Tx ⊆ g(X) for all x ∈ X.
(2) g(X) is a G-complete subspace of X.
(3) g and T are weakly compatible.
(4) HG(Tx, Ty, Tz) ≤ α(G(gx, gy, gz))G(gx, gy, gz) for all x, y, z ∈ X.
Proof. The proofs of (1), (2), and (3) are clear. By (1), we have
To prove (4), let x, y, z ∈ X. If x = y = z = 0, then
Thus, we may assume that x, y, and z are not all zero. With out loss of generality, we assume that x ≤ y ≤ z. Then
Since x ≤ y ≤ z, so
This implies that
This yields that
This yields that
We deduce that
On the other hand, it is obvious that all other hypotheses of Theorem 2.1 are satisfied and so g and T have a unique common fixed point, which is u = 0.
Remark 1• Theorem 2.1 improves Kaewcharoen and Kaewkhao [[34], Theorem 3.3] (in case b = c = d = 0).
• Corollary 2.3 generalizes Mustafa [[15], Theorem 5.1.7] and Shatanawi [[35], Corollary 3.4].
Competing interests
The authors declare that they have no competing interests.
Authors' contributions
The authors have contributed in obtaining the new results presented in this article. All authors read and approved the final manuscript.
Acknowledgements
The authors thank the editor and the referees for their useful comments and suggestions.
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