Abstract
In this paper, we show the impact of certain general results by the author on the topic described in the title. Here is a sample:
Let
be a real Hilbert space and let
be a nonexpansive potential operator.
Then, the following alternative holds: either T has a fixed point, or, for each sphere S centered at 0, the restriction to S of the functional
has a unique global maximum towards which each maximizing sequence in S converges.
MSC: 47H09, 47H10, 47J30, 47N10, 49K40, 90C31.
Keywords:
nonexpansive operator; potential operator; fixed point; well-posedness1 Introduction
There is no doubt that fixed point theory for nonexpansive mappings is one of the central topics in modern analysis. Actually, since [1,4,5], such a theory has had (and continues to have) a strong development, and several deep (often spectacular) results have been achieved within it in the settings such as abstract harmonic analysis (where the contributions of Professor Lau are fundamental) and the geometry of Banach spaces.
On the other hand, another very important class of operators is that composed of potential operators. That is to say, the operators that can be regarded as the Gâteaux derivative of a suitable functional. Actually, the variational methods to study linear and nonlinear equations are fully based on potential operators.
In the present paper, as the title says, we are interested in fixed point theory for the intersection of the two above classes of operators in the setting of Hilbert spaces. More precisely, we intend to show the impact of certain general results that the author has established in the last years on such a topic.
Referring to [11] for a thorough introduction to potential operators (with several examples related
to them), we recall here a specific situation where one can easily appreciate the
relationships between the two classes of operators we are dealing with. Namely, let
be a real Hilbert space,
a continuous linear operator and
. Then,
is a potential operator if and only if
for all
, while it is nonexpansive if and only if
.
The following result subsumes very well the spirit of the ones that we will establish in Section 3:
Theorem 1.1Let
be a real Hilbert space and let
be a nonexpansive potential operator. Then, the following alternative holds: eitherThas a fixed point, or, for each sphereScentered at 0, the restriction toSof the functional
has a unique global maximum towards which each maximizing sequence inSconverges.
2 Preliminaries
From now on,
will be a real Hilbert space.

and
will be a nonexpansive operator, i.e.,
for all
. We also assume that there exists a Gâteaux differentiable functional
, with
, such that
, where
is the Gâteaux derivative of J. This amounts to say that
for all
. It can easily be checked that
We also put
for all
,
. For
we will simply use the symbol I instead of
.
The basic proposition which relates the fixed points of λT (
) with the functional
is as follows.
Proposition 2.1The functional
is strictly convex and coercive for
, and convex for
. Hence, for each
, the fixed points ofλTagree with the global minima of the functional
.
Proof Let
. For each
, we have
From this, it follows that the derivative of the functional
(that is the operator
) is monotone and that it is uniformly monotone if
. Now, the conclusion follows from classical results ([11], pp.247-249). □
Another very useful proposition [7] is as follows.
Proposition 2.2LetYbe a nonempty set,
two functions, andλ, μtwo real numbers, with
. Let
be a global minimum of the function
and let
be a global minimum of the function
.
Then, one has
If either
or
is strict and
, then
Let S be a topological space. As usual, given a function
and a set
, we say that the problem of minimizing (resp. maximizing) f over C is well posed if the following two conditions hold:
– the restriction of f to C has a unique global minimum (resp. maximum), say
;
– every sequence
in C such that
(resp.
), converges to
.
A set of the type
is said to be a sub-level set of f.
Given two functionals
, for each
, we denote by
either the set of all global minima of
or the empty set according to whether
or
. We adopt the conventions
,
. We also set

Note that, by Proposition 2.2, if
, one has
In [8], we established the following basic result:
Theorem 2.1Let
and let
, with
. Assume that
and that, for each
, the functional
has weakly compact sub-level sets and admits a unique global minimum inX.
Then, for each
, the problem of minimizing Ψ over
is well posed with respect to the weak topology. More precisely, the unique global minimum of
, say
, agrees with the unique global minimum of
for some
. Moreover, the functions
and
are continuous in
with respect to the weak topology.
Finally, let us recall the result of M. Schechter and K. Tintarev [10] that we will apply jointly with Theorem 2.1 in the next section.
Theorem 2.2Assume thatJis sequentially weakly continuous. For each
, set
Moreover, let
be an open interval such that, for each
has no local maxima in
and there exists a unique
satisfying
.
Then, the following conclusions hold:
(i) the functionψis
and increasing inA;
3 Results
Our first result (inspired by [6]) shows the key role which a certain function
plays in dealing with the fixed points of T.
If there is
such that
, thenThas a fixed point which lies in
.
In any case, one has
Proof Let
be such that
. So, there exists
, such that
By Proposition 2.1, I is weakly lower semicontinuous, and so there exists
such that
for all
. We claim that
. Actually, if
, then, by (3.1), taking into account that
, we would have
against (3.2). As a consequence,
is a local minimum of the functional I, and so it is a fixed point of T, by Proposition 2.1 again.
Now, assume that
. Arguing by contradiction, suppose that
Then, we could find a sequence of positive numbers
converging to 0 such that
for all
. But then, for each
, there would be a fixed point
of T lying in
. Hence,
would converge to 0 in X and so, by continuity, we would have
.
Now, to prove the third assertion, assume that T has a fixed point, say
. Then, by Proposition 2.1, we have
for all
. Fix
. From (3.3), we then obtain
and so
This clearly implies that
Fix
. So, λT has a (unique) fixed point. By the previous remark, we clearly infer that
and so the conclusion is obtained passing to the limit for λ tending to 1. □
Note the following corollary of Theorem 3.1.
Corollary 3.1IfThas no fixed points, then
The next two results come from Theorem 2.1. Clearly,
(resp.
) will denote the set of all fixed points of T (resp. −T).
For each
, let
be the unique fixed point of the operatorλT.
Then, the following assertions hold:
(
) the function
is increasing in
and its range is
;
(
) for each
, the point
is the unique point of minimal norm of
towards which every minimizing sequence in
, for the norm, converges;
(
) the function
is continuous in
.
Proof We apply Theorem 2.1 taking

and

for all
. With these choices, we have
and
By Propositions 2.1 and 2.2, the function g is non-decreasing in
and
. Now, let
be a non-degenerate interval. If g was constant in A, then, by Proposition 2.2 again, the function
would be constant in A. Let
be its unique value. Then, we would have
for all
. This would imply that
, and so
, against the assumption. Consequently, g is increasing in
. Since, for
, the functional
is weakly lower semicontinuous, coercive and with a unique global minimum (that is
), we are allowed to apply Theorem 2.1. Accordingly, for each
, there exists
, with
, such that
for all
, and each sequence
in
with
, weakly converges to
. Since X is a Hilbert space, this implies that
strongly converges to
. Likewise, we get the strong continuity in
of the function
from its weak continuity that is ensured by Theorem 2.1 too. Now, to get (
), (
), (
), it is enough to observe that
For each
, let
be the unique fixed point of the operator
.
Then, the following assertions hold:
(
) the function
is decreasing in
and its range is
;
(
) for each
, the point
is the unique global maximum of
towards which every maximizing sequence for
converges;
(
) the function
is continuous in
.
If, in addition, the functionalJis sequentially weakly continuous and has no local maxima in
, then, withψdefined as in Theorem 2.2, the following further assertions hold:
(
) the functionψis
, increasing and strictly concave in
;
Proof This time, we apply Theorem 2.1 taking

and

for all
. With these choices, we have
and
Since
and
is closed, we have
. Of course, for each
, the functional
is weakly lower semicontinuous, coercive and with a unique global minimum (that is
), and so we can derive (
), (
), (
) from Theorem 2.1, reasoning as in the proof of Theorem 3.2. Under the additional
assumptions on J, (
), (
) follow directly from Theorem 2.2, taking
. Finally, (
) is a consequence of (
) and of the fact that
. □
Remark 3.1 Of course, Theorem 1.1 is a by-product of Theorem 3.3, as, if T has no fixed points, we have
. On the other hand, if, for some
, the problem of maximizing J over
is not well posed, then T has a fixed point lying in
. Indeed, from (
) it follows that
. But,
is a closed and convex set. So, it admits a point of minimal norm. By the above inequality,
such a point lies in
and we are done.
Now, we want to present the form that Theorem 3.3 assumes when T is an affine operator.
As usual, for a linear operator
, we say that
– L is compact if, for each bounded set
, the set
is compact;
– L is symmetric if
Theorem 3.4Let
be a symmetric continuous linear operator, with norm 1, and let
.
For each
, let
be the unique fixed point of the operator
. Moreover, set
where
Then, the following assertions hold:
(
) the function
is decreasing in
and its range is
;
(
) for each
, the point
is the unique global maximum of
towards which every maximizing sequence for
converges;
(
) the function
is continuous in
.
If, in addition, Tis compact, then the following further assertions hold:
(
) the functionδis
, increasing and strictly concave in
;
Before giving the proof of Theorem 3.4, we establish the following
Proposition 3.1Let
be a symmetric continuous linear operator and letHbe defined as in Theorem 3.4.
Then, for
, the following are equivalent:
Proof First, observe that the symmetry of L is equivalent to the fact that the functional H is Gâteaux differentiable with derivative given by
for all
([11], p.235). By the symmetry of L again, it is easy to check that, for each
, the inequality
is equivalent to
Now, if (j) holds, then
(that is
) and there is
such that (3.4) holds for all
. So, from (3.5), we have
for all
and then, by linearity, for all
, and this shows (jjj). Vice versa, if (jjj) holds, then (3.5) is satisfied for all
and so by (3.4),
is a global maximum of H, and the proof is complete. □
Proof of Theorem 3.4 As we observed above, the symmetry of L is equivalent to the fact that L agrees with the derivative of H. So, since
, we can apply Theorem 3.3 taking
. In such a way, we derive (
)-(
) directly from (
)-(
). Now, assume that L is also compact. Then, this implies that H is sequentially weakly continuous ([11], Corollary 41.9). Suppose that H has a local maximum, say
. Then, by Proposition 3.1,
is a global maximum of H. In particular, this implies that the functional
is coercive and hence, by sequential weak lower semicontinuity, it has a global minimum.
That is,
, by Proposition 2.1. So, by Proposition 2.2, it clearly follows that
In other words, H has no local maxima in
. At this point, (
)-(
) come directly from (
)-(
). □
Some remarks on Theorem 3.4 are now in order.
Remark 3.2 Note that the compactness of L serves only to guarantee that the functional
is sequentially weakly continuous. So, Theorem 3.4 actually holds under such a weaker
condition.
Remark 3.3 A natural question is: if assertions (
)-(
) hold, must the operator L be symmetric and the functional
sequentially weakly continuous?
Remark 3.4 Note that if L, besides being compact and symmetric, is also positive (i.e.,
), then, by classical results, the operator
is not surjective, and so there are
for which the conclusion of Theorem 3.4 holds with
.
In the previous results, the essential assumption is that
. In the next (and last) result, to the contrary, we highlight a remarkable uniqueness
property occurring when
(and so
). Actually, in such a case, 0 is the unique fixed point of λT for each
.
More precisely, for each real Hilbert space
, we denote by
the class of all nonexpansive potential operators
such that
Set
We have:
Theorem 3.5For any real Hilbert space
, with
, one has
We first prove
Proposition 3.2One has
Proof Let
. Fix
. Let us prove that 0 is the only fixed point of λP. Arguing by contradiction, assume that
is a non-zero fixed point of λP. It is not restrictive to assume that
(otherwise, we would work with
). Consider now the function
defined by
So, in particular, we get
which contradicts the fact
. From what we have just proven, it clearly follows that
Now, fix any
. Continue to consider the function χ defined above (for a fixed
). Clearly, the function
belongs to
and
Of course, from this we infer that
and the conclusion clearly follows. □
Proof of Theorem 3.5 First, let us prove that
To this end, fix any
and any
such that
for some
. Fix also
, with
, and consider the operator
defined by
for all
. Clearly,
. Finally, set
we also have
and so
From this, it clearly follows that
and so (3.6) follows now from Proposition 3.2.
Now, let us prove that
To this end, fix
,
and
such that
Then, consider the function
defined by
for all
. Clearly, the primitive of Q vanishing at 0 is non-positive in R. Moreover, for each
, we have
This shows that Q is nonexpansive, and so
. Now, from (3.8), we get
that is
From this, we infer that
So (3.7) follows from Proposition 3.2, and the proof is complete. □
For specific consequences of Theorem 3.5 concerning nonlinear elliptic equations, we refer to the very interesting papers [2] and [3] where a problem asked in [9] was solved.
Competing interests
The author declares that he has no competing interest.
Acknowledgement
Dedicated to Professor Anthony To-Ming Lau, with esteem and friendship.
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