Abstract
In this paper, the common solution problem (P1) of generalized equilibrium problems
for a system of inverse-strongly monotone mappings
and a system of bifunctions
satisfying certain conditions, and the common fixed-point problem (P2) for a family
of uniformly quasi-ϕ-asymptotically nonexpansive and locally uniformly Lipschitz continuous or uniformly
Hölder continuous mappings
are proposed. A new iterative sequence is constructed by using the generalized projection
and hybrid method, and a strong convergence theorem is proved on approximating a common
solution of (P1) and (P2) in Banach space.
2000 MSC: 26B25, 40A05
Keywords:
Common solution; Equilibrium problem; Fixed-point problem; Iterative sequence; Strong convergence1. Introduction
Recently, common solution problems (i.e., to find a common element of the set of solutions of equilibrium problems and/or the set of fixed points of mappings and/or the set of solutions of variational inequalities) with their applications have been discussed. Some authors such as in references [1-7] presented various iterative schemes and showed some strong or weak convergence theorems on common solution problems in Hilbert spaces. In 2008-2009, Takahashi and Zembayashi [8,9] introduced several iterative sequences on finding a common solution of an equilibrium problem and a fixed-point problem for a relatively nonexpansive mapping, and established some strong or weak convergence theorems. In 2010, Chang et al. [10] discussed the common solution of a generalized equilibrium problem and a common fixed-point problem for two relatively nonexpansive mappings, and established a strong convergence theorem on the common solution problem. The frameworks of spaces in [8-10] are the uniformly smooth and uniformly convex Banach spaces. Chang et al. [11] established a strong convergence theorem on solving the common fixed-point problem for a family of uniformly quasi-ϕ-asymptotically nonexpansive and uniformly Lipschitz continuous mappings in a uniformly smooth and strictly convex Banach space with the Kadec-Klee property. Some other problems such as optimization problems (e.g. see [1,4,6]) and common zero-point problems (e.g. see [10]) are closely related to common solution problems.
Throughout this paper, unless other stated, ℝ and
are denoted by the set of the real numbers and the set {1, 2,..., N}, respectively, where N is any given positive integer. Let E be a real Banach space with the norm || · ||, E* be the dual of E, and 〈·,·〉 be the pairing between E and E*. Suppose that C is a nonempty closed convex subset of E.
Let
be N mappings and
be N bifunctions. For each
, the generalized equilibrium problem for fk and Ak is to seek
such that
(1.1)The common solution problem (P1) of generalized equilibrium problems for
and
is to seek an element in
, where
and G(k) is the set of solutions of (1.1). We write G instead of
in the case of N = 1.
Let
be a family of mappings. The common fixed-point problem (P2) for
is to seek an element in
, where
and F (Si) is the set of fixed points of Si.
Motivated by the works in [8-11], in this paper we will produce a new iterative sequence approximating a common solution
of (P1) and (P2) (i.e., some point belonging to
), and show a strong convergence theorem in a uniformly smooth and strictly convex
Banach space with the Kadec-Klee property, where
in (P2) is a family of uniformly quasi-ϕ-asymptotically nonexpansive mappings and for each i ≥ 1, Si is locally uniformly Lipschitz continuous or uniformly Hölder continuous with order
Θi .
2. Preliminaries
Let E be a real Banach space, and {xn} be a sequence in E. We denote by xn → x and xn ⇀ x the strong convergence and weak convergence of {xn}, respectively. The normalized duality mapping J : E → 2E* is defined by

By the Hahn-Banach theorem, Jx ≠ ∅ for each x ∈ E.
A Banach space E is said to be strictly convex if
for all x, y ∈ U = {u ∈ E : ||u|| = 1} with x ≠ y; to be uniformly convex if for each ε ∈ (0, 2], there exists γ > 0 such that
for all x, y ∈ U with ||x - y|| ≥ ε; to be smooth if the limit
(2.1)exists for every x, y ∈ U; to be uniformly smooth if the limit (2.1) exists uniformly for all x, y ∈ U.
Remark 2.1. The basic properties below hold (see [12]).
(i) If E is a real uniformly smooth Banach space, then J is uniformly continuous on each bounded subset of E.
(ii) If E is a strictly convex reflexive Banach space, then J-1 is hemicontinuous, that is, J-1 is norm-to-weak*-continuous.
(iii) If E is a smooth and strictly convex reflexive Banach space, then J is single-valued, one-to-one and onto.
(iv) Each uniformly convex Banach space E has the Kadec-Klee property, that is, for any sequence {xn} ⊂ E, if xn ⇀ x ∈ E and ||xn|| → ||x||, then xn → x.
(v) A Banach space E is uniformly smooth if and only if E* is uniformly convex.
(vi) A Banach space E is strictly convex if and only if J is strictly monotone, that is,

(vii) Both uniformly smooth Banach spaces and uniformly convex Banach spaces are reflexive.
Now let E be a smooth and strictly convex reflexive Banach space. As Alber [13] and Kamimura and Takahashi [14] did, the Lyapunov functional ϕ : E × E → ℝ+ is defined by

It follows from [15] that ϕ(x, y) = 0 if and only if x = y, and that
(2.2)Further suppose that C is a nonempty closed convex subset of E. The generalized projection (see [13]) ΠC: E→C is defined by for each x ∈ E,

A mapping A : C → E* is said to be δ-inverse-strongly monotone, if there exists a constant δ > 0 such that

A mapping S : C → C is said to be closed if for each {xn} ⊂ C, xn → x and Sxn → y imply Sx = y; to be quasi-ϕ-asymptotically nonexpansive (see [16]) if F(S) ≠ ∅, and there exists a sequence {ln} ⊂ [1, ∞) with ln → 1 such that

It is easy to see that if A : C → E* is δ-inverse-strongly monotone, then A is
-Lipschitz continuous. The class of quasi-ϕ-asymptotically nonexpansive mappings contains properly the class of relatively nonexpansive
mappings (see [17]) as a subclass.
Definition 2.1 (see [11]). Let
be a sequence of mappings.
is said to be a family of uniformly quasi-ϕ-asymptotically nonexpansive mappings, if
and there exists a sequence {ln} ⊂ [1, ∞) with ln → 1 such that for each i ≥ 1,

Now we introduce the following concepts.
Definition 2.2. A mapping S : C → C is said
(1) to be locally uniformly Lipschitz continuous if for any bounded subset D in C, there exists a constant LD > 0 such that

(2) to be uniformly Hölder continuous with order Θ (Θ > 0) if there exists a constant L > 0 such that

Remark 2.2. It is easy to see that any uniformly Lipschitz continuous mapping (see [11]) is locally uniformly Lipschitz continuous, and is also uniformly Hölder continuous with order Θ = 1. However, the converse is not true.
Example 2.1. Suppose that S : ℝ → ℝ is defined by

Then S is locally uniformly Lipschitz continuous. In fact, for any bounded subset D in ℝ, setting M = 1 + sup{|x| : x ∈ D}, we have |Snx - Sny| ≤ 2M |x - y|, x, y ∈ D, ∀n ≥ 1. But S fails to be uniformly Lipschitz continuous.
Example 2.2. Suppose that S : ℝ - ℝ is defined by

S is uniformly Hölder continuous with order
, since
, ∀x, y ∈ ℝ, ∀n ≥ 1. But S fails to be uniformly Lipschitz continuous.
Lemma 2.1 (see [13,14]). If C is a nonempty closed convex subset of a smooth and strictly convex reflexive Banach space E, then
(1) ϕ(x, ΠC(y)) + ϕ(ΠC(y), y) ≥ ϕ(x, y), ∀x ∈ C, y ∈ E;
(2) for × ∈ E and u ∈ C, one has

□
Lemma 2.2. Let E be a uniformly smooth and strictly convex Banach space with the Kadec-Klee property, {xn} and{yn} be two sequences of E, and
. If
and ϕ(xn, yn) → 0, then
.
Proof. We complete this proof by two steps.
Step 1. Show that there exists a subsequence
of {yn} such that
.
In fact, since ϕ(xn, yn) → 0, by (2.2) we have ||xn|| - ||yn|| → 0. It follows from
that
(2.3)and so
(2.4)Then {Jyn} is bounded in E*. It follows from Remark 2.1(v) and (vii) that E* is reflexive. Hence there exist a point f0 ∈ E* and a subsequence
of {Jyn} such that
(2.5)It follows from Remark 2.1(vii) and (iii) that there exists a point x ∈ E such that Jx = f0. By the definition of ϕ, we obtain

By weak lower semicontinuity of norm || · ||, we have

which implies that
and
. It follows from Remark 2.1(iv) and (v) that E* has the Kadec-Klee property, and so
by (2.4) and (2.5). By Remark 2.1(vii) and (ii), we have
, which implies that
by (2.3) and the Kadec-Klee property of E.
Step 2. Show that
.
In fact, suppose that
. For some given number ε0 > 0, there exists a positive integer sequence {nk} with n1 < n2 < · · · < nk < · · ·, such that
(2.6)Replacing {yn} by
in Step 1, there exists a subsequence
of
such that
, which contradicts (2.6). □
Lemma 2.3. Let C be a nonempty closed convex subset of a smooth and strictly convex reflexive Banach space E, and let A : C → E* be a δ-inverse-strongly monotone mapping and f : C × C → ℝ be a bifunction satisfying the following conditions
(B1) f(z, z) = 0, ∀z ∈ C;
(B2)
;
(B3) for any z ∈ C, the function y α f(z, y) is convex and lower semicontinuous;
(B4) for some β ≥ 0 with β ≤ δ,

Then the following conclusions hold:
(1) For any r > 0 and u ∈ E, there exists a unique point z ∈ C such that
(2.7)(2) For any given r > 0, define a mapping Kr : E → C as follows: ∀u ∈ E,

We have (i) F(Kr) = G and G is closed convex in C, where

(ii) ϕ(z, Kru) + ϕ(Kru, u) ≤ ϕ(z, u), ∀z ∈ F(Kr).
(3) For each n ≥ 1, rn > a > 0 and un ∈ C with
, we have

Proof. (1) We consider the bifunction
instead of f. It follows from the proof of Lemma 2.5 in [10] that
satisfies (B1)-(B3). Since A is δ-inverse-strongly monotone, by (B4), we have
(2.8)which implies
is monotone. By Blum amd Oettli [18], for any r > 0 and u ∈ E, there exists z ∈ C such that (2.7) holds. Next we show that (2.7) has a unique solution. If for any given
r > 0 and u ∈ E, z1 and z2 are two solutions of (2.7), then

and

Adding these two inequalities, we have

It follows from (2.8) that

which implies that z1 = z2 by Remark 2.1(vi).
(2) Since
satisfies (B1)-(B3) and is monotone, the conclusion (2) follows from Lemmas 2.8 and 2.9 in [9].
(3) Since

we have
(2.9)by the monotonicity of
. It follows from
. rn > a > 0 and Remark 2.1(i) that

Since
is convex and lower semicontinuous, it is also weakly lower semicontinuous. Letting
n → ∞ in (2.9), we have
, ∀y ∈ C. For any t ∈ (0, 1] and y ∈ C, setting
, we have yt ∈ C and
, which together with (B1) implies that

Thus f(yt, y) + 〈y - yt, Ayt〉 ≥ 0, ∀y ∈ C, ∀t ∈ (0, 1]. Letting t ↓ 0, since z α f(z, y) + 〈y - z, Az〉 satisfies (B2), we have
, ∀y ∈ C.
Remark 2.3. If β = 0 in (B4), that is, f is monotone, then the conclusions (1) and (2) in Lemma 2.3 reduce to the relating results of Lemmas 2.5 and 2.6 in [10], respectively.
Next we give an example to show that there exist the mapping A and the bifunction f satisfying the conditions of Lemma 2.3. However, f is not monotone.
Example 2.3. Define A : ℝ → ℝ and f : ℝ × ℝ → ℝ by
∈ ∀x ∈ ℝ and
, ∀(x, y) ∈ ℝ × ℝ, respectively. It is easy to see that A is
-inverse-strongly monotone, f satisfies (B1)-(B3), and
, ∀(x, y) : ℝ × ℝ with
.
Lemma 2.4 (see [12]). Let C be a nonempty closed convex subset of a real uniformly smooth and strictly convex Banach space E with the Kadec-Klee property, S : C → C be a closed and quasi-ϕ-asymptotically nonexpansive mapping with a sequence {ln} ⊂ [1, ∞), ln → 1. Then F(S) is closed convex in C.
Lemma 2.5 (see [11]). Let E be a uniformly convex Banach space, η > 0 be a positive number and Bη(0) be a closed ball of E. Then, for any given sequence
and for any given
with
, there exists a continuous, strictly increasing and convex function g : [0, 2η) → [0, ∞) with g(0) = 0 such that for any positive integers i, j with i < j,

□
3. Strong convergence theorem
In this section, let C be a nonempty closed convex subset of a real uniformly smooth and strictly convex Banach space E with the Kadec-Klee property.
Theorem 3.1. Suppose that
(C1) for each
, the mapping Ak : C → E* is δk-inverse-strongly monotone, the bifunction fk : C × C → ℝ satisfies (B1)-(B3), and for some βk ≥ 0 with βk ≤ δk,

(C2)
is a family of closed and uniformly quasi-ϕ-asymptotically nonexpansive mappings with a sequence {ln} ⊂ [1, ∞), ln → 1;
(C3) for each i ≥ 1, Si is either locally uniformly Lipschitz continuous or uniformly Hölder continuous with
order Θi (Θi > 0), and
is bounded in C.
(C4)
. Take the sequence
generated by

where for each
,
with some a > 0,
, and
. If
, ∀n ≥ 0 and lim infn→∞ αn,0 αn, i > 0, ∀i ≥ 1, then
.
Proof. We shall complete this proof by seven steps below.
Step 1. Show that
,
, Hn and Wn for all n ≥ 0 are closed convex.
In fact,
is closed convex since for each i ≥ 1, F(Si) is closed convex by (C2) and Lemma 2.4.
is closed convex since for each
, G(k) is closed convex by (C1) and Lemma 2.3(2)(i). H0 = C is closed convex. Since ϕ(v,uN,n) ≤ ϕ(v,xn) + ξn is equivalent to

we know that Hn(n ≥ 0) are closed convex. Finally, Wn is closed convex by its definition. Thus
and
are well defined.
Step 2. Show that {xn} and
are bounded.
From
, ∀n ≥ 0 and Lemma 2.1(1), we have
(3.1)which implies that {ϕ(xn, x0)} is bounded, and so is {xn} by (2.2). It follows from (C2) that for all
, i ≥ 1, n ≥ 1,

Hence for all i ≥ 1,
is uniformly bounded, and so is
by (2.2). Obviously,
(3.2)Step 3. Show that
, ∀n ≥ 0.
Since Banach space E is uniformly smooth, E* is uniformly convex, by Remark 2.1(v). For any given
, any n ≥ 1 and any positive integer j, by (C2) and Lemma 2.5, we have
(3.3)Put
,
, ∀n ≥ 0. It follows from (3.3) and Lemma 2.3(2)(ii) that
(3.4)which implies that if
, then p ∈ Hn, ∀n ≥ 0. Hence,
, ∀n ≥ 0. By induction, now we prove that
, ∀n ≥ 0. In fact, it follows from W0 = C that
. Suppose that
for some m ≥ 0. By the definition of
and Lemma 2.1(2), we have

and so

which shows z ∈ Wm+1, so
.
Step 4. Show that there exists
such that
.
Without loss of generalization, we can assume that
, since {xn} is bounded and E is reflexive. Moreover, it follows that
, ∀n ≥ 0 from Hn+1 ∩ Wn+1 ⊂ Hn ∩ Wn and the closeness and convexity of Hn ∩ Wn. Noting that

we have

by (3.1). It follows that
(3.5)and so
by
. Hence,
(3.6)by the Kadec-Klee property of E, and so
(3.7)by Remark 2.1(i).
Step 5. Show that
.
Since xn+1 ∈ C, setting u = xn+1 in (3.1), we have

By (3.5),
(3.8)By xn+1 ∈ Hn+1, (3.2) and (3.8), we have

which together with (3.6) and Lemma 2.2 implies that
(3.9)For any j ≥ 1 and any given
, it follows from (3.2)-(3.4) and (3.9) that
(3.10)which implies that

since
, ∀i ≥ 1. We obtain
(3.11)since g(0) = 0 and g is strictly increasing and continuous. By (3.7) and (3.11), we have
and
for all j ≥ 1. It follows from Remark 2.1(ii) that
, which implies
(3.12)by the uniform boundedness of
and the Kadec-Klee property of E. Thus

By (C3) and (3.6), we have

Hence, for each j ≥ 1,

By (3.12) and the closeness of Sj, we have
for all j ≥ 1 and so
.
Step 6. Show that
.
In fact, it is easy to see that for each
, and
, the sequence {ϕ(p, uk,n)} is bounded by (3.2), (3.4) and the boundedness of {xn} and
, which implies that {uk,n} is bounded in C by (2.2). Since
, by (3.2), (3.3), (3.5) and (3.10), we have

It follows from Lemma 2.2 that
(3.13)Furthermore, it follows from (3.4) and Lemma 2.3(2)(ii) that for any given
,

which implies

by Remark 2.1(i), (3.9) and (3.13). Then
by (3.13) and Lemma 2.2. Similarly, we also obtain
. Hence, together with (3.9) and (3.13), for each
,
(3.14)For each
, since
, we have

which together with (3.14) and Lemma 2.3(3) implies that
, ∀y ∈ C. Therefore
and so
.
Step 7. Show that
.
In fact, letting
, by
and
, we have

It follows from (3.6) that

Hence,
, and so
. □
Setting N = 1, u0,n = yn and uN,n = un in Theorem 3.1, we can obtain the following result.
Corollary 3.1 Suppose that
(D1) the mapping A : C → E* is a mapping with δ -inverse-strongly monotone, the bifunction f : C × C → ℝ satisfies (B1)-(B3) and for some β > 0 with β ≤ δ,

(D2) both (C2) and (C3) hold, and
Take the sequence
generated by

where
,
for some a > 0 and
. If
, ∀n ≥ 0 and lim infn→∞ αn,0αn,i > 0, ∀i ≥ 1, then
. □
Furthermore, if Si = S, i ≥ 1 in Corollary 3.1, the following corollary can be obtained immediately.
Corollary 3.2. Suppose that, besides (D1),
(E1) S : C → C is closed and quasi-ϕ-asymptotically nonexpansive with {ln} ⊂ [1, ∞), ln → 1;
(E2) S is either locally uniformly Lipschitz continuous or uniformly Hölder continuous
with order Θ (Θ > 0), F(S) is bounded in C and F(S) ∩ G ≠ ∅. Take the sequence
generated by

where
,
for some a > 0 and ξ = supu∈F(S)(ln -1)ϕ(u, xn) . If lim infn→∞ αn(1- αn) > 0, then
. □
Competing interests
The authors declare that they have no completing interests.
Authors' contributions
All the authors read and approved the final manuscript.
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